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authorAndrea Canciani <ranma42@gmail.com>2011-07-15 22:02:01 +0200
committerAndrea Canciani <ranma42@gmail.com>2011-07-15 22:05:11 +0200
commitc06af104546868ed748c8f771817f5e9ae9a6a2d (patch)
treec4e50cbebc8c969feec4f675238d384687887fa9 /pixman
parente814b50877bf313619fbf777dcab98d39874f8a4 (diff)
radial: Improve documentation and naming
Add a comment to explain why the tests guarantee that the code always computes the greatest valid root. Rename "det" as "discr" to make it match the mathematical name "discriminant". Based on a patch by Jeff Muizelaar <jmuizelaar@mozilla.com>.
Diffstat (limited to 'pixman')
-rw-r--r--pixman/pixman-radial-gradient.c31
1 files changed, 21 insertions, 10 deletions
diff --git a/pixman/pixman-radial-gradient.c b/pixman/pixman-radial-gradient.c
index 5e9fd73..ecbca6f 100644
--- a/pixman/pixman-radial-gradient.c
+++ b/pixman/pixman-radial-gradient.c
@@ -78,11 +78,11 @@ radial_compute_color (double a,
{
/*
* In this function error propagation can lead to bad results:
- * - det can have an unbound error (if b*b-a*c is very small),
+ * - discr can have an unbound error (if b*b-a*c is very small),
* potentially making it the opposite sign of what it should have been
* (thus clearing a pixel that would have been colored or vice-versa)
- * or propagating the error to sqrtdet;
- * if det has the wrong sign or b is very small, this can lead to bad
+ * or propagating the error to sqrtdiscr;
+ * if discr has the wrong sign or b is very small, this can lead to bad
* results
*
* - the algorithm used to compute the solutions of the quadratic
@@ -92,7 +92,7 @@ radial_compute_color (double a,
*
* - the above problems are worse if a is small (as inva becomes bigger)
*/
- double det;
+ double discr;
if (a == 0)
{
@@ -116,15 +116,26 @@ radial_compute_color (double a,
return 0;
}
- det = fdot (b, a, 0, b, -c, 0);
- if (det >= 0)
+ discr = fdot (b, a, 0, b, -c, 0);
+ if (discr >= 0)
{
- double sqrtdet, t0, t1;
+ double sqrtdiscr, t0, t1;
- sqrtdet = sqrt (det);
- t0 = (b + sqrtdet) * inva;
- t1 = (b - sqrtdet) * inva;
+ sqrtdiscr = sqrt (discr);
+ t0 = (b + sqrtdiscr) * inva;
+ t1 = (b - sqrtdiscr) * inva;
+ /*
+ * The root that must be used if the biggest one that belongs
+ * to the valid range ([0,1] for PIXMAN_REPEAT_NONE, any
+ * solution that results in a positive radius otherwise).
+ *
+ * If a > 0, t0 is the biggest solution, so if it is valid, it
+ * is the correct result.
+ *
+ * If a < 0, only one of the solutions can be valid, so the
+ * order in which they are tested is not important.
+ */
if (repeat == PIXMAN_REPEAT_NONE)
{
if (0 <= t0 && t0 <= pixman_fixed_1)