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authorChris Wilson <chris@chris-wilson.co.uk>2009-01-15 00:26:03 +0000
committerChris Wilson <chris@chris-wilson.co.uk>2009-01-29 10:10:39 +0000
commit48f9a0e6da0dd24ea9c809876ef3c745dcfd0d52 (patch)
treea54cd32856407e2c2fdd88de9ae38fcb8eca0ff4 /src/cairo-spline.c
parentee7ac5681fa6a74b68beeae667d96d1421050fc9 (diff)
[spline] Correct the definition of a cubic Bezier curve.
Add the missing coefficients for p1 and p2 so the derivation of the derivative and the solution for its inflection points stands correct.
Diffstat (limited to 'src/cairo-spline.c')
-rw-r--r--src/cairo-spline.c8
1 files changed, 4 insertions, 4 deletions
diff --git a/src/cairo-spline.c b/src/cairo-spline.c
index 414e0536..948516e1 100644
--- a/src/cairo-spline.c
+++ b/src/cairo-spline.c
@@ -234,7 +234,7 @@ _cairo_spline_bound (cairo_spline_add_point_func_t add_point_func,
/* The spline can be written as a polynomial of the four points:
*
- * (1-t)³p0 + t(1-t)²p1 + t²(1-t)p2 + t³p3
+ * (1-t)³p0 + 3t(1-t)²p1 + 3t²(1-t)p2 + t³p3
*
* for 0≤t≤1. Now, the X and Y components of the spline follow the
* same polynomial but with x and y replaced for p. To find the
@@ -244,13 +244,13 @@ _cairo_spline_bound (cairo_spline_add_point_func_t add_point_func,
*
* Here is the derivative of the curve, sorted on t:
*
- * 3t²(-p0+3p1-3p2+p3) + 6t(3p0-6p1+3p2) -3p0+3p1
+ * 3t²(-p0+3p1-3p2+p3) + 2t(3p0-6p1+3p2) -3p0+3p1
*
* Let:
*
* a = -p0+3p1-3p2+p3
- * b = 3p0-6p1+3p2
- * c = -3p0+3p1
+ * b = p0-2p1+p2
+ * c = -p0+p1
*
* Gives:
*