Add a way to delete an individual set of job results.

People have been asking for a way to delete bad jobs.

Signed-off-by: Martin Bligh <mbligh@google.com>



git-svn-id: svn://test.kernel.org/autotest/trunk@968 592f7852-d20e-0410-864c-8624ca9c26a4

1 files changed, 23 insertions, 0 deletions

diff --git a/tko/delete_job_results b/tko/delete_job_results
new file mode 100644
index 00000000..ec4c1060
--- /dev/null
+++ b/tko/delete_job_results
@@ -0,0 +1,23 @@
+#!/usr/bin/python
+import os, sys, shutil
+thisdir = os.path.dirname(os.path.abspath(sys.argv[0]))
+sys.path.insert(0, os.path.abspath(os.path.join(thisdir, '../tko')))
+import db
+
+usage = "usage: delete_job_results <job tag>"
+
+if len(sys.argv) < 2:
+	print usage
+	sys.exit(2)
+tag = sys.argv[1]
+resultsdir = os.path.abspath(os.path.join(thisdir, '../results', tag))
+
+if not os.path.isdir(resultsdir):
+	raise "Results directory %s does not exist" % resultsdir
+db = db.db()
+if not db.find_job(tag):
+	raise "Job tag %s does not exist in database" % tag
+
+shutil.rmtree(resultsdir)
+db.delete_job(tag)
+