From 1987b1b8f9f17a06255877e7917d0bb5b5377774 Mon Sep 17 00:00:00 2001 From: Bartosz Golaszewski Date: Thu, 11 Apr 2019 11:49:44 +0200 Subject: um: irq: don't set the chip for all irqs Setting a chip for an interrupt marks it as allocated. Since UM doesn't support dynamic interrupt numbers (yet), it means we cannot simply increase NR_IRQS and then use the free irqs between LAST_IRQ and NR_IRQS with gpio-mockup or iio testing drivers as irq_alloc_descs() will fail after not being able to neither find an unallocated range of interrupts nor expand the range. Only call irq_set_chip_and_handler() for irqs until LAST_IRQ. Signed-off-by: Bartosz Golaszewski Reviewed-by: Anton Ivanov Acked-by: Anton Ivanov Signed-off-by: Richard Weinberger --- arch/um/kernel/irq.c | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) (limited to 'arch/um') diff --git a/arch/um/kernel/irq.c b/arch/um/kernel/irq.c index f4874b7ec503..598d7b3d9355 100644 --- a/arch/um/kernel/irq.c +++ b/arch/um/kernel/irq.c @@ -479,7 +479,7 @@ void __init init_IRQ(void) irq_set_chip_and_handler(TIMER_IRQ, &SIGVTALRM_irq_type, handle_edge_irq); - for (i = 1; i < NR_IRQS; i++) + for (i = 1; i < LAST_IRQ; i++) irq_set_chip_and_handler(i, &normal_irq_type, handle_edge_irq); /* Initialize EPOLL Loop */ os_setup_epoll(); -- cgit v1.2.3