From 6244917f377bf64719551b58592a02a0336a7439 Mon Sep 17 00:00:00 2001 From: Daniel Thompson Date: Wed, 24 Apr 2024 15:03:37 +0100 Subject: kdb: Merge identical case statements in kdb_read() The code that handles case 14 (down) and case 16 (up) has been copy and pasted despite being byte-for-byte identical. Combine them. Cc: stable@vger.kernel.org # Not a bug fix but it is needed for later bug fixes Reviewed-by: Douglas Anderson Tested-by: Justin Stitt Link: https://lore.kernel.org/r/20240424-kgdb_read_refactor-v3-4-f236dbe9828d@linaro.org Signed-off-by: Daniel Thompson --- kernel/debug/kdb/kdb_io.c | 10 +--------- 1 file changed, 1 insertion(+), 9 deletions(-) diff --git a/kernel/debug/kdb/kdb_io.c b/kernel/debug/kdb/kdb_io.c index 5fccb46f399e..a73779529803 100644 --- a/kernel/debug/kdb/kdb_io.c +++ b/kernel/debug/kdb/kdb_io.c @@ -317,6 +317,7 @@ poll_again: } break; case 14: /* Down */ + case 16: /* Up */ memset(tmpbuffer, ' ', strlen(kdb_prompt_str) + (lastchar-buffer)); *(tmpbuffer+strlen(kdb_prompt_str) + @@ -331,15 +332,6 @@ poll_again: ++cp; } break; - case 16: /* Up */ - memset(tmpbuffer, ' ', - strlen(kdb_prompt_str) + (lastchar-buffer)); - *(tmpbuffer+strlen(kdb_prompt_str) + - (lastchar-buffer)) = '\0'; - kdb_printf("\r%s\r", tmpbuffer); - *lastchar = (char)key; - *(lastchar+1) = '\0'; - return lastchar; case 9: /* Tab */ if (tab < 2) ++tab; -- cgit v1.2.3