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authorRussell King <rmk+kernel@arm.linux.org.uk>2012-03-10 11:32:34 +0000
committerRussell King <rmk+kernel@arm.linux.org.uk>2012-05-13 17:12:16 +0100
commit1bc39ac5dab265b76ce6e20d6c85f900539fd190 (patch)
tree03cd4a54b1a44d7f2b346536e6be6fc9e8b9d7cd /arch/arm/mach-versatile
parentb28626da344ea3d9f9c518a6c082db9306f534ff (diff)
ARM: PCI: versatile: fix PCI interrupt setup
This is at odds with the documentation in the file; it says pin 1 on slots 24,25,26,27 map to IRQs 27,28,29,30, but the function will always be entered with slot=0 due to the lack of swizzle function. Fix this function to behave as the comments say, and use the standard PCI swizzle. Signed-off-by: Russell King <rmk+kernel@arm.linux.org.uk>
Diffstat (limited to 'arch/arm/mach-versatile')
-rw-r--r--arch/arm/mach-versatile/pci.c6
1 files changed, 2 insertions, 4 deletions
diff --git a/arch/arm/mach-versatile/pci.c b/arch/arm/mach-versatile/pci.c
index d2268be8c34c..24dd4b1490bd 100644
--- a/arch/arm/mach-versatile/pci.c
+++ b/arch/arm/mach-versatile/pci.c
@@ -339,15 +339,13 @@ static int __init versatile_map_irq(const struct pci_dev *dev, u8 slot, u8 pin)
* 26 1 29
* 27 1 30
*/
- irq = 27 + ((slot + pin - 1) & 3);
-
- printk("PCI map irq: slot %d, pin %d, devslot %d, irq: %d\n",slot,pin,devslot,irq);
+ irq = 27 + ((slot - 24 + pin - 1) & 3);
return irq;
}
static struct hw_pci versatile_pci __initdata = {
- .swizzle = NULL,
+ .swizzle = pci_std_swizzle,
.map_irq = versatile_map_irq,
.nr_controllers = 1,
.setup = pci_versatile_setup,